13(y-4)=3(4y+7)-73

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Solution for 13(y-4)=3(4y+7)-73 equation: 



13(y-4)=3(4y+7)-73

We move all terms to the left:

13(y-4)-(3(4y+7)-73)=0

We multiply parentheses

13y-(3(4y+7)-73)-52=0



We calculate terms in parentheses: -(3(4y+7)-73), so:

3(4y+7)-73

We multiply parentheses

12y+21-73

We add all the numbers together, and all the variables

12y-52

Back to the equation:

-(12y-52)



We get rid of parentheses

13y-12y+52-52=0

We add all the numbers together, and all the variables

y=0

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