13(z+3)-5(z-3)=3(z-2)+4(z-3)

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Solution for 13(z+3)-5(z-3)=3(z-2)+4(z-3) equation: 



13(z+3)-5(z-3)=3(z-2)+4(z-3)

We move all terms to the left:

13(z+3)-5(z-3)-(3(z-2)+4(z-3))=0

We multiply parentheses

13z-5z-(3(z-2)+4(z-3))+39+15=0



We calculate terms in parentheses: -(3(z-2)+4(z-3)), so:

3(z-2)+4(z-3)

We multiply parentheses

3z+4z-6-12

We add all the numbers together, and all the variables

7z-18

Back to the equation:

-(7z-18)



We add all the numbers together, and all the variables

8z-(7z-18)+54=0

We get rid of parentheses

8z-7z+18+54=0

We add all the numbers together, and all the variables

z+72=0

We move all terms containing z to the left, all other terms to the right

z=-72

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