13(z+3)=13z+39

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Solution for 13(z+3)=13z+39 equation: 



13(z+3)=13z+39

We move all terms to the left:

13(z+3)-(13z+39)=0

We multiply parentheses

13z-(13z+39)+39=0

We get rid of parentheses

13z-13z-39+39=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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