13(z+4)-4(z-1=4(z-2)+4(z-3)

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Solution for 13(z+4)-4(z-1=4(z-2)+4(z-3) equation: 



13(z+4)-4(z-1=4(z-2)+4(z-3)

We move all terms to the left:

13(z+4)-4(z-1-(4(z-2)+4(z-3))=0

We multiply parentheses

13z-4(z-1-(4(z-2)+4(z-3))+52=0

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