13(z+4)-5(z-3)=5(z-1)+2(z-3)

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Solution for 13(z+4)-5(z-3)=5(z-1)+2(z-3) equation: 



13(z+4)-5(z-3)=5(z-1)+2(z-3)

We move all terms to the left:

13(z+4)-5(z-3)-(5(z-1)+2(z-3))=0

We multiply parentheses

13z-5z-(5(z-1)+2(z-3))+52+15=0



We calculate terms in parentheses: -(5(z-1)+2(z-3)), so:

5(z-1)+2(z-3)

We multiply parentheses

5z+2z-5-6

We add all the numbers together, and all the variables

7z-11

Back to the equation:

-(7z-11)



We add all the numbers together, and all the variables

8z-(7z-11)+67=0

We get rid of parentheses

8z-7z+11+67=0

We add all the numbers together, and all the variables

z+78=0

We move all terms containing z to the left, all other terms to the right

z=-78

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