13(z+4)-6=23(5-z)

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Solution for 13(z+4)-6=23(5-z) equation: 



13(z+4)-6=23(5-z)

We move all terms to the left:

13(z+4)-6-(23(5-z))=0

We add all the numbers together, and all the variables

13(z+4)-(23(-1z+5))-6=0

We multiply parentheses

13z-(23(-1z+5))+52-6=0



We calculate terms in parentheses: -(23(-1z+5)), so:

23(-1z+5)

We multiply parentheses

-23z+115

Back to the equation:

-(-23z+115)



We add all the numbers together, and all the variables

13z-(-23z+115)+46=0

We get rid of parentheses

13z+23z-115+46=0

We add all the numbers together, and all the variables

36z-69=0

We move all terms containing z to the left, all other terms to the right

36z=69

z=69/36

z=1+11/12

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