13(z-3)-3(z-1)=5(z-3)+4(z-3)

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Solution for 13(z-3)-3(z-1)=5(z-3)+4(z-3) equation: 



13(z-3)-3(z-1)=5(z-3)+4(z-3)

We move all terms to the left:

13(z-3)-3(z-1)-(5(z-3)+4(z-3))=0

We multiply parentheses

13z-3z-(5(z-3)+4(z-3))-39+3=0



We calculate terms in parentheses: -(5(z-3)+4(z-3)), so:

5(z-3)+4(z-3)

We multiply parentheses

5z+4z-15-12

We add all the numbers together, and all the variables

9z-27

Back to the equation:

-(9z-27)



We add all the numbers together, and all the variables

10z-(9z-27)-36=0

We get rid of parentheses

10z-9z+27-36=0

We add all the numbers together, and all the variables

z-9=0

We move all terms containing z to the left, all other terms to the right

z=9

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