13(z-4)-3(z-9)-5(2+z)=0

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Solution for 13(z-4)-3(z-9)-5(2+z)=0 equation: 



13(z-4)-3(z-9)-5(2+z)=0

We add all the numbers together, and all the variables

13(z-4)-3(z-9)-5(z+2)=0

We multiply parentheses

13z-3z-5z-52+27-10=0

We add all the numbers together, and all the variables

5z-35=0

We move all terms containing z to the left, all other terms to the right

5z=35

z=35/5

z=7

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