13+(2c+2)=2(c+2)+3c

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Solution for 13+(2c+2)=2(c+2)+3c equation: 



13+(2c+2)=2(c+2)+3c

We move all terms to the left:

13+(2c+2)-(2(c+2)+3c)=0

We get rid of parentheses

2c-(2(c+2)+3c)+2+13=0



We calculate terms in parentheses: -(2(c+2)+3c), so:

2(c+2)+3c

We add all the numbers together, and all the variables

3c+2(c+2)

We multiply parentheses

3c+2c+4

We add all the numbers together, and all the variables

5c+4

Back to the equation:

-(5c+4)



We add all the numbers together, and all the variables

2c-(5c+4)+15=0

We get rid of parentheses

2c-5c-4+15=0

We add all the numbers together, and all the variables

-3c+11=0

We move all terms containing c to the left, all other terms to the right

-3c=-11

c=-11/-3

c=3+2/3

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