13+(6-2x)=7+(7x+3)

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Solution for 13+(6-2x)=7+(7x+3) equation: 



13+(6-2x)=7+(7x+3)

We move all terms to the left:

13+(6-2x)-(7+(7x+3))=0

We add all the numbers together, and all the variables

(-2x+6)-(7+(7x+3))+13=0

We get rid of parentheses

-2x-(7+(7x+3))+6+13=0



We calculate terms in parentheses: -(7+(7x+3)), so:

7+(7x+3)

determiningTheFunctionDomain
(7x+3)+7

We get rid of parentheses

7x+3+7

We add all the numbers together, and all the variables

7x+10

Back to the equation:

-(7x+10)



We add all the numbers together, and all the variables

-2x-(7x+10)+19=0

We get rid of parentheses

-2x-7x-10+19=0

We add all the numbers together, and all the variables

-9x+9=0

We move all terms containing x to the left, all other terms to the right

-9x=-9

x=-9/-9

x=1

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