13+2(1-4)=8u-5(u+7

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Solution for 13+2(1-4)=8u-5(u+7 equation: 



13+2(1-4)=8u-5(u+7

We move all terms to the left:

13+2(1-4)-(8u-5(u+7)=0

We add all the numbers together, and all the variables

-(8u-5(u+7)+13+2(-3)=0



We calculate terms in parentheses: -(8u-5(u+7)+13+2(-3), so:

8u-5(u+7)+13+2(-3

We add all the numbers together, and all the variables

8u-5(u+7)

We multiply parentheses

8u-5u-35

We add all the numbers together, and all the variables

3u-35

Back to the equation:

-(3u-35)



We get rid of parentheses

-3u+35=0

We move all terms containing u to the left, all other terms to the right

-3u=-35

u=-35/-3

u=11+2/3

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