13+2(1-x)=8x-5(x+7)

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Solution for 13+2(1-x)=8x-5(x+7) equation: 



13+2(1-x)=8x-5(x+7)

We move all terms to the left:

13+2(1-x)-(8x-5(x+7))=0

We add all the numbers together, and all the variables

2(-1x+1)-(8x-5(x+7))+13=0

We multiply parentheses

-2x-(8x-5(x+7))+2+13=0



We calculate terms in parentheses: -(8x-5(x+7)), so:

8x-5(x+7)

We multiply parentheses

8x-5x-35

We add all the numbers together, and all the variables

3x-35

Back to the equation:

-(3x-35)



We add all the numbers together, and all the variables

-2x-(3x-35)+15=0

We get rid of parentheses

-2x-3x+35+15=0

We add all the numbers together, and all the variables

-5x+50=0

We move all terms containing x to the left, all other terms to the right

-5x=-50

x=-50/-5

x=+10

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