13+2(3x-4)=41

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Solution for 13+2(3x-4)=41 equation: 



13+2(3x-4)=41

We move all terms to the left:

13+2(3x-4)-(41)=0

We add all the numbers together, and all the variables

2(3x-4)-28=0

We multiply parentheses

6x-8-28=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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