13+2(6c-2)=29

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Solution for 13+2(6c-2)=29 equation: 



13+2(6c-2)=29

We move all terms to the left:

13+2(6c-2)-(29)=0

We add all the numbers together, and all the variables

2(6c-2)-16=0

We multiply parentheses

12c-4-16=0

We add all the numbers together, and all the variables

12c-20=0

We move all terms containing c to the left, all other terms to the right

12c=20

c=20/12

c=1+2/3

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