13+2-4x=3(3x+1)

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Solution for 13+2-4x=3(3x+1) equation: 



13+2-4x=3(3x+1)

We move all terms to the left:

13+2-4x-(3(3x+1))=0

We add all the numbers together, and all the variables

-4x-(3(3x+1))+15=0



We calculate terms in parentheses: -(3(3x+1)), so:

3(3x+1)

We multiply parentheses

9x+3

Back to the equation:

-(9x+3)



We get rid of parentheses

-4x-9x-3+15=0

We add all the numbers together, and all the variables

-13x+12=0

We move all terms containing x to the left, all other terms to the right

-13x=-12

x=-12/-13

x=12/13

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