13+3(4-x)=x-7+2(x-2)

Solution for 13+3(4-x)=x-7+2(x-2) equation:

13+3(4-x)=x-7+2(x-2)

We move all terms to the left:

13+3(4-x)-(x-7+2(x-2))=0

We add all the numbers together, and all the variables

3(-1x+4)-(x-7+2(x-2))+13=0

We multiply parentheses

-3x-(x-7+2(x-2))+12+13=0


We calculate terms in parentheses: -(x-7+2(x-2)), so:

x-7+2(x-2)

determiningTheFunctionDomain
x+2(x-2)-7

We multiply parentheses

x+2x-4-7

We add all the numbers together, and all the variables

3x-11

Back to the equation:

-(3x-11)


We add all the numbers together, and all the variables

-3x-(3x-11)+25=0

We get rid of parentheses

-3x-3x+11+25=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6