13+3x=15x2+13+63x

Solution for 13+3x=15x2+13+63x equation:

13+3x=15x^2+13+63x

We move all terms to the left:

13+3x-(15x^2+13+63x)=0

We get rid of parentheses

-15x^2+3x-63x-13+13=0

We add all the numbers together, and all the variables

-15x^2-60x=0

a = -15; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·(-15)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*-15}=\frac{0}{-30}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*-15}=\frac{120}{-30}
=-4
$