13+3x=3(-x+3)-26

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Solution for 13+3x=3(-x+3)-26 equation: 



13+3x=3(-x+3)-26

We move all terms to the left:

13+3x-(3(-x+3)-26)=0

We add all the numbers together, and all the variables

3x-(3(-1x+3)-26)+13=0



We calculate terms in parentheses: -(3(-1x+3)-26), so:

3(-1x+3)-26

We multiply parentheses

-3x+9-26

We add all the numbers together, and all the variables

-3x-17

Back to the equation:

-(-3x-17)



We get rid of parentheses

3x+3x+17+13=0

We add all the numbers together, and all the variables

6x+30=0

We move all terms containing x to the left, all other terms to the right

6x=-30

x=-30/6

x=-5

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