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13+6/5x=23-9x
We move all terms to the left:
13+6/5x-(23-9x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
6/5x-(-9x+23)+13=0
We get rid of parentheses
6/5x+9x-23+13=0
We multiply all the terms by the denominator
9x*5x-23*5x+13*5x+6=0
Wy multiply elements
45x^2-115x+65x+6=0
We add all the numbers together, and all the variables
45x^2-50x+6=0
a = 45; b = -50; c = +6;
Δ = b2-4ac
Δ = -502-4·45·6
Δ = 1420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1420}=\sqrt{4*355}=\sqrt{4}*\sqrt{355}=2\sqrt{355}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{355}}{2*45}=\frac{50-2\sqrt{355}}{90} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{355}}{2*45}=\frac{50+2\sqrt{355}}{90} $
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