13+6z=7(z-2)

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Solution for 13+6z=7(z-2) equation: 



13+6z=7(z-2)

We move all terms to the left:

13+6z-(7(z-2))=0



We calculate terms in parentheses: -(7(z-2)), so:

7(z-2)

We multiply parentheses

7z-14

Back to the equation:

-(7z-14)



We get rid of parentheses

6z-7z+14+13=0

We add all the numbers together, and all the variables

-1z+27=0

We move all terms containing z to the left, all other terms to the right

-z=-27

z=-27/-1

z=+27

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