13-(-y-5)=3(y+3)-9(y+3)

Solution for 13-(-y-5)=3(y+3)-9(y+3) equation:

13-(-y-5)=3(y+3)-9(y+3)

We move all terms to the left:

13-(-y-5)-(3(y+3)-9(y+3))=0

We add all the numbers together, and all the variables

-(-1y-5)-(3(y+3)-9(y+3))+13=0

We get rid of parentheses

1y-(3(y+3)-9(y+3))+5+13=0


We calculate terms in parentheses: -(3(y+3)-9(y+3)), so:

3(y+3)-9(y+3)

We multiply parentheses

3y-9y+9-27

We add all the numbers together, and all the variables

-6y-18

Back to the equation:

-(-6y-18)


We add all the numbers together, and all the variables

y-(-6y-18)+18=0

We get rid of parentheses

y+6y+18+18=0

We add all the numbers together, and all the variables

7y+36=0

We move all terms containing y to the left, all other terms to the right

7y=-36

y=-36/7

y=-5+1/7