13-(2-3y)=6+2y-(5+y)

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Solution for 13-(2-3y)=6+2y-(5+y) equation: 



13-(2-3y)=6+2y-(5+y)

We move all terms to the left:

13-(2-3y)-(6+2y-(5+y))=0

We add all the numbers together, and all the variables

-(-3y+2)-(6+2y-(y+5))+13=0

We get rid of parentheses

3y-(6+2y-(y+5))-2+13=0



We calculate terms in parentheses: -(6+2y-(y+5)), so:

6+2y-(y+5)

determiningTheFunctionDomain
2y-(y+5)+6

We get rid of parentheses

2y-y-5+6

We add all the numbers together, and all the variables

y+1

Back to the equation:

-(y+1)



We add all the numbers together, and all the variables

3y-(y+1)+11=0

We get rid of parentheses

3y-y-1+11=0

We add all the numbers together, and all the variables

2y+10=0

We move all terms containing y to the left, all other terms to the right

2y=-10

y=-10/2

y=-5

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