13-(20+2)=2(c+2)+3c

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Solution for 13-(20+2)=2(c+2)+3c equation:


Simplifying
13 + -1(20 + 2) = 2(c + 2) + 3c

Combine like terms: 20 + 2 = 22
13 + -1(22) = 2(c + 2) + 3c

Multiply -1 * 22
13 + -22 = 2(c + 2) + 3c

Combine like terms: 13 + -22 = -9
-9 = 2(c + 2) + 3c

Reorder the terms:
-9 = 2(2 + c) + 3c
-9 = (2 * 2 + c * 2) + 3c
-9 = (4 + 2c) + 3c

Combine like terms: 2c + 3c = 5c
-9 = 4 + 5c

Solving
-9 = 4 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
-9 + -5c = 4 + 5c + -5c

Combine like terms: 5c + -5c = 0
-9 + -5c = 4 + 0
-9 + -5c = 4

Add '9' to each side of the equation.
-9 + 9 + -5c = 4 + 9

Combine like terms: -9 + 9 = 0
0 + -5c = 4 + 9
-5c = 4 + 9

Combine like terms: 4 + 9 = 13
-5c = 13

Divide each side by '-5'.
c = -2.6

Simplifying
c = -2.6

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