13-(2a+2)=2(c+2)+3c

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Solution for 13-(2a+2)=2(c+2)+3c equation:


Simplifying
13 + -1(2a + 2) = 2(c + 2) + 3c

Reorder the terms:
13 + -1(2 + 2a) = 2(c + 2) + 3c
13 + (2 * -1 + 2a * -1) = 2(c + 2) + 3c
13 + (-2 + -2a) = 2(c + 2) + 3c

Combine like terms: 13 + -2 = 11
11 + -2a = 2(c + 2) + 3c

Reorder the terms:
11 + -2a = 2(2 + c) + 3c
11 + -2a = (2 * 2 + c * 2) + 3c
11 + -2a = (4 + 2c) + 3c

Combine like terms: 2c + 3c = 5c
11 + -2a = 4 + 5c

Solving
11 + -2a = 4 + 5c

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + -2a = 4 + -11 + 5c

Combine like terms: 11 + -11 = 0
0 + -2a = 4 + -11 + 5c
-2a = 4 + -11 + 5c

Combine like terms: 4 + -11 = -7
-2a = -7 + 5c

Divide each side by '-2'.
a = 3.5 + -2.5c

Simplifying
a = 3.5 + -2.5c

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