13-(2c+2)=2(C+2+3c

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Solution for 13-(2c+2)=2(C+2+3c equation: 



13-(2c+2)=2(+2+3c

We move all terms to the left:

13-(2c+2)-(2(+2+3c)=0

We add all the numbers together, and all the variables

-(2c+2)-(2(3c+2)+13=0

We get rid of parentheses

-2c-(2(3c+2)+13-2=0

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