13-(2c+2)=2(c+2)+2

Solution for 13-(2c+2)=2(c+2)+2 equation:

Simplifying
13 + -1(2c + 2) = 2(c + 2) + 2

Reorder the terms:
13 + -1(2 + 2c) = 2(c + 2) + 2
13 + (2 * -1 + 2c * -1) = 2(c + 2) + 2
13 + (-2 + -2c) = 2(c + 2) + 2

Combine like terms: 13 + -2 = 11
11 + -2c = 2(c + 2) + 2

Reorder the terms:
11 + -2c = 2(2 + c) + 2
11 + -2c = (2 * 2 + c * 2) + 2
11 + -2c = (4 + 2c) + 2

Reorder the terms:
11 + -2c = 4 + 2 + 2c

Combine like terms: 4 + 2 = 6
11 + -2c = 6 + 2c

Solving
11 + -2c = 6 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
11 + -2c + -2c = 6 + 2c + -2c

Combine like terms: -2c + -2c = -4c
11 + -4c = 6 + 2c + -2c

Combine like terms: 2c + -2c = 0
11 + -4c = 6 + 0
11 + -4c = 6

Add '-11' to each side of the equation.
11 + -11 + -4c = 6 + -11

Combine like terms: 11 + -11 = 0
0 + -4c = 6 + -11
-4c = 6 + -11

Combine like terms: 6 + -11 = -5
-4c = -5

Divide each side by '-4'.
c = 1.25

Simplifying
c = 1.25