13-(2c+2)=2(c+2)+3c

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Solution for 13-(2c+2)=2(c+2)+3c equation: 


Simplifying
13 + -1(2c + 2) = 2(c + 2) + 3c

Reorder the terms:
13 + -1(2 + 2c) = 2(c + 2) + 3c
13 + (2 * -1 + 2c * -1) = 2(c + 2) + 3c
13 + (-2 + -2c) = 2(c + 2) + 3c

Combine like terms: 13 + -2 = 11
11 + -2c = 2(c + 2) + 3c

Reorder the terms:
11 + -2c = 2(2 + c) + 3c
11 + -2c = (2 * 2 + c * 2) + 3c
11 + -2c = (4 + 2c) + 3c

Combine like terms: 2c + 3c = 5c
11 + -2c = 4 + 5c

Solving
11 + -2c = 4 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
11 + -2c + -5c = 4 + 5c + -5c

Combine like terms: -2c + -5c = -7c
11 + -7c = 4 + 5c + -5c

Combine like terms: 5c + -5c = 0
11 + -7c = 4 + 0
11 + -7c = 4

Add '-11' to each side of the equation.
11 + -11 + -7c = 4 + -11

Combine like terms: 11 + -11 = 0
0 + -7c = 4 + -11
-7c = 4 + -11

Combine like terms: 4 + -11 = -7
-7c = -7

Divide each side by '-7'.
c = 1

Simplifying
c = 1

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