13-(2c+2)=2c(c+2)+3c

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Solution for 13-(2c+2)=2c(c+2)+3c equation: 


Simplifying
13 + -1(2c + 2) = 2c(c + 2) + 3c

Reorder the terms:
13 + -1(2 + 2c) = 2c(c + 2) + 3c
13 + (2 * -1 + 2c * -1) = 2c(c + 2) + 3c
13 + (-2 + -2c) = 2c(c + 2) + 3c

Combine like terms: 13 + -2 = 11
11 + -2c = 2c(c + 2) + 3c

Reorder the terms:
11 + -2c = 2c(2 + c) + 3c
11 + -2c = (2 * 2c + c * 2c) + 3c
11 + -2c = (4c + 2c2) + 3c

Reorder the terms:
11 + -2c = 4c + 3c + 2c2

Combine like terms: 4c + 3c = 7c
11 + -2c = 7c + 2c2

Solving
11 + -2c = 7c + 2c2

Solving for variable 'c'.

Combine like terms: -2c + -7c = -9c
11 + -9c + -2c2 = 7c + 2c2 + -7c + -2c2

Reorder the terms:
11 + -9c + -2c2 = 7c + -7c + 2c2 + -2c2

Combine like terms: 7c + -7c = 0
11 + -9c + -2c2 = 0 + 2c2 + -2c2
11 + -9c + -2c2 = 2c2 + -2c2

Combine like terms: 2c2 + -2c2 = 0
11 + -9c + -2c2 = 0

Factor a trinomial.
(1 + -1c)(11 + 2c) = 0


Subproblem 1
Set the factor '(1 + -1c)' equal to zero and attempt to solve:

Simplifying
1 + -1c = 0

Solving
1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1c = 0 + -1
-1c = 0 + -1

Combine like terms: 0 + -1 = -1
-1c = -1

Divide each side by '-1'.
c = 1

Simplifying
c = 1

Subproblem 2
Set the factor '(11 + 2c)' equal to zero and attempt to solve:

Simplifying
11 + 2c = 0

Solving
11 + 2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 2c = 0 + -11

Combine like terms: 11 + -11 = 0
0 + 2c = 0 + -11
2c = 0 + -11

Combine like terms: 0 + -11 = -11
2c = -11

Divide each side by '2'.
c = -5.5

Simplifying
c = -5.5
Solution
c = {1, -5.5}

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