13-(2c+3)=2(c+2)+3c

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Solution for 13-(2c+3)=2(c+2)+3c equation:


Simplifying
13 + -1(2c + 3) = 2(c + 2) + 3c

Reorder the terms:
13 + -1(3 + 2c) = 2(c + 2) + 3c
13 + (3 * -1 + 2c * -1) = 2(c + 2) + 3c
13 + (-3 + -2c) = 2(c + 2) + 3c

Combine like terms: 13 + -3 = 10
10 + -2c = 2(c + 2) + 3c

Reorder the terms:
10 + -2c = 2(2 + c) + 3c
10 + -2c = (2 * 2 + c * 2) + 3c
10 + -2c = (4 + 2c) + 3c

Combine like terms: 2c + 3c = 5c
10 + -2c = 4 + 5c

Solving
10 + -2c = 4 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
10 + -2c + -5c = 4 + 5c + -5c

Combine like terms: -2c + -5c = -7c
10 + -7c = 4 + 5c + -5c

Combine like terms: 5c + -5c = 0
10 + -7c = 4 + 0
10 + -7c = 4

Add '-10' to each side of the equation.
10 + -10 + -7c = 4 + -10

Combine like terms: 10 + -10 = 0
0 + -7c = 4 + -10
-7c = 4 + -10

Combine like terms: 4 + -10 = -6
-7c = -6

Divide each side by '-7'.
c = 0.8571428571

Simplifying
c = 0.8571428571

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