13-(2c+c)=2(c+2)+3c

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Solution for 13-(2c+c)=2(c+2)+3c equation:


Simplifying
13 + -1(2c + c) = 2(c + 2) + 3c

Combine like terms: 2c + c = 3c
13 + -1(3c) = 2(c + 2) + 3c

Remove parenthesis around (3c)
13 + -1 * 3c = 2(c + 2) + 3c

Multiply -1 * 3
13 + -3c = 2(c + 2) + 3c

Reorder the terms:
13 + -3c = 2(2 + c) + 3c
13 + -3c = (2 * 2 + c * 2) + 3c
13 + -3c = (4 + 2c) + 3c

Combine like terms: 2c + 3c = 5c
13 + -3c = 4 + 5c

Solving
13 + -3c = 4 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
13 + -3c + -5c = 4 + 5c + -5c

Combine like terms: -3c + -5c = -8c
13 + -8c = 4 + 5c + -5c

Combine like terms: 5c + -5c = 0
13 + -8c = 4 + 0
13 + -8c = 4

Add '-13' to each side of the equation.
13 + -13 + -8c = 4 + -13

Combine like terms: 13 + -13 = 0
0 + -8c = 4 + -13
-8c = 4 + -13

Combine like terms: 4 + -13 = -9
-8c = -9

Divide each side by '-8'.
c = 1.125

Simplifying
c = 1.125

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