13-(2f+2)=2(f+2)+3f

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Solution for 13-(2f+2)=2(f+2)+3f equation: 


Simplifying
13 + -1(2f + 2) = 2(f + 2) + 3f

Reorder the terms:
13 + -1(2 + 2f) = 2(f + 2) + 3f
13 + (2 * -1 + 2f * -1) = 2(f + 2) + 3f
13 + (-2 + -2f) = 2(f + 2) + 3f

Combine like terms: 13 + -2 = 11
11 + -2f = 2(f + 2) + 3f

Reorder the terms:
11 + -2f = 2(2 + f) + 3f
11 + -2f = (2 * 2 + f * 2) + 3f
11 + -2f = (4 + 2f) + 3f

Combine like terms: 2f + 3f = 5f
11 + -2f = 4 + 5f

Solving
11 + -2f = 4 + 5f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-5f' to each side of the equation.
11 + -2f + -5f = 4 + 5f + -5f

Combine like terms: -2f + -5f = -7f
11 + -7f = 4 + 5f + -5f

Combine like terms: 5f + -5f = 0
11 + -7f = 4 + 0
11 + -7f = 4

Add '-11' to each side of the equation.
11 + -11 + -7f = 4 + -11

Combine like terms: 11 + -11 = 0
0 + -7f = 4 + -11
-7f = 4 + -11

Combine like terms: 4 + -11 = -7
-7f = -7

Divide each side by '-7'.
f = 1

Simplifying
f = 1

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