13-(2k+2)=2(k+2)+3k

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Solution for 13-(2k+2)=2(k+2)+3k equation: 



13-(2k+2)=2(k+2)+3k

We move all terms to the left:

13-(2k+2)-(2(k+2)+3k)=0

We get rid of parentheses

-2k-(2(k+2)+3k)-2+13=0



We calculate terms in parentheses: -(2(k+2)+3k), so:

2(k+2)+3k

We add all the numbers together, and all the variables

3k+2(k+2)

We multiply parentheses

3k+2k+4

We add all the numbers together, and all the variables

5k+4

Back to the equation:

-(5k+4)



We add all the numbers together, and all the variables

-2k-(5k+4)+11=0

We get rid of parentheses

-2k-5k-4+11=0

We add all the numbers together, and all the variables

-7k+7=0

We move all terms containing k to the left, all other terms to the right

-7k=-7

k=-7/-7

k=1

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