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13-(2x+2)=2(5+x)=3(x+1)
We move all terms to the left:
13-(2x+2)-(2(5+x))=0
We add all the numbers together, and all the variables
-(2x+2)-(2(x+5))+13=0
We get rid of parentheses
-2x-(2(x+5))-2+13=0
We calculate terms in parentheses: -(2(x+5)), so:We add all the numbers together, and all the variables
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
-2x-(2x+10)+11=0
We get rid of parentheses
-2x-2x-10+11=0
We add all the numbers together, and all the variables
-4x+1=0
We move all terms containing x to the left, all other terms to the right
-4x=-1
x=-1/-4
x=1/4
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