13-(8x+5)=-4(1+3x)

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Solution for 13-(8x+5)=-4(1+3x) equation: 



13-(8x+5)=-4(1+3x)

We move all terms to the left:

13-(8x+5)-(-4(1+3x))=0

We add all the numbers together, and all the variables

-(8x+5)-(-4(3x+1))+13=0

We get rid of parentheses

-8x-(-4(3x+1))-5+13=0



We calculate terms in parentheses: -(-4(3x+1)), so:

-4(3x+1)

We multiply parentheses

-12x-4

Back to the equation:

-(-12x-4)



We add all the numbers together, and all the variables

-8x-(-12x-4)+8=0

We get rid of parentheses

-8x+12x+4+8=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3

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