13-(x-3)=2(x-2)+5

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Solution for 13-(x-3)=2(x-2)+5 equation: 



13-(x-3)=2(x-2)+5

We move all terms to the left:

13-(x-3)-(2(x-2)+5)=0

We get rid of parentheses

-x-(2(x-2)+5)+3+13=0



We calculate terms in parentheses: -(2(x-2)+5), so:

2(x-2)+5

We multiply parentheses

2x-4+5

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

-1x-(2x+1)+16=0

We get rid of parentheses

-1x-2x-1+16=0

We add all the numbers together, and all the variables

-3x+15=0

We move all terms containing x to the left, all other terms to the right

-3x=-15

x=-15/-3

x=+5

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