13-2(3x-1)=18-4(2x+1)+3x

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Solution for 13-2(3x-1)=18-4(2x+1)+3x equation: 



13-2(3x-1)=18-4(2x+1)+3x

We move all terms to the left:

13-2(3x-1)-(18-4(2x+1)+3x)=0

We multiply parentheses

-6x-(18-4(2x+1)+3x)+2+13=0



We calculate terms in parentheses: -(18-4(2x+1)+3x), so:

18-4(2x+1)+3x

determiningTheFunctionDomain
-4(2x+1)+3x+18

We add all the numbers together, and all the variables

3x-4(2x+1)+18

We multiply parentheses

3x-8x-4+18

We add all the numbers together, and all the variables

-5x+14

Back to the equation:

-(-5x+14)



We add all the numbers together, and all the variables

-6x-(-5x+14)+15=0

We get rid of parentheses

-6x+5x-14+15=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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