13-5x(-8x)=-40

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Solution for 13-5x(-8x)=-40 equation: 



13-5x(-8x)=-40

We move all terms to the left:

13-5x(-8x)-(-40)=0

We add all the numbers together, and all the variables

-5x(-8x)+53=0

We multiply parentheses

40x^2+53=0

a = 40; b = 0; c = +53;
Δ = b2-4ac
Δ = 02-4·40·53
Δ = -8480
Delta is less than zero, so there is no solution for the equation

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