13-7(x+2)=11-5(x+4)

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Solution for 13-7(x+2)=11-5(x+4) equation: 



13-7(x+2)=11-5(x+4)

We move all terms to the left:

13-7(x+2)-(11-5(x+4))=0

We multiply parentheses

-7x-(11-5(x+4))-14+13=0



We calculate terms in parentheses: -(11-5(x+4)), so:

11-5(x+4)

determiningTheFunctionDomain
-5(x+4)+11

We multiply parentheses

-5x-20+11

We add all the numbers together, and all the variables

-5x-9

Back to the equation:

-(-5x-9)



We add all the numbers together, and all the variables

-7x-(-5x-9)-1=0

We get rid of parentheses

-7x+5x+9-1=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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