13/(x+2)=8/(x-1)

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Solution for 13/(x+2)=8/(x-1) equation: 



13/(x+2)=8/(x-1)

We move all terms to the left:

13/(x+2)-(8/(x-1))=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (x-1))!=0

x∈R



We calculate fractions


13x/((x+2)*(x-1)))+(-(8*(x+2))/((x+2)*(x-1)))=0



We calculate terms in parentheses: -(8*(x+2))/((x+2)*(x-1))), so:

8*(x+2))/((x+2)*(x-1))

We multiply all the terms by the denominator


8*(x+2))

We multiply parentheses

8x+

We add all the numbers together, and all the variables

8x

Back to the equation:

-(8x)



We add all the numbers together, and all the variables

-8x+13x/((x+2)*(x-1)))+(=0

We multiply all the terms by the denominator


-8x*((x+2)*(x-1)))+(+13x=0

We add all the numbers together, and all the variables

13x-8x*((x+2)*(x-1)))+(=0

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