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13/12x+1/12x=8x+1/6=11/12x
We move all terms to the left:
13/12x+1/12x-(8x+1/6)=0
Domain of the equation: 12x!=0We add all the numbers together, and all the variables
x!=0/12
x!=0
x∈R
13/12x+1/12x-(+8x+1/6)=0
We get rid of parentheses
13/12x+1/12x-8x-1/6=0
We calculate fractions
There is no solution for this equation
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