13/12x=3/4x+4

Solution for 13/12x=3/4x+4 equation:

13/12x=3/4x+4

We move all terms to the left:

13/12x-(3/4x+4)=0


Domain of the equation: 12x!=0

x!=0/12

x!=0

x∈R



Domain of the equation: 4x+4)!=0

x∈R


We get rid of parentheses

13/12x-3/4x-4=0

We calculate fractions


52x/48x^2+(-36x)/48x^2-4=0

We multiply all the terms by the denominator


52x+(-36x)-4*48x^2=0

Wy multiply elements

-192x^2+52x+(-36x)=0

We get rid of parentheses

-192x^2+52x-36x=0

We add all the numbers together, and all the variables

-192x^2+16x=0

a = -192; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-192)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-192}=\frac{-32}{-384}
=1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-192}=\frac{0}{-384}
=0
$