13/2y-5/y=1/3

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Solution for 13/2y-5/y=1/3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(13/2)*y-(5/y) = 1/3 // - 1/3

(13/2)*y-(5/y)-(1/3) = 0

(13/2)*y-5*y^-1-1/3 = 0

13/2*y^1-5*y^-1-1/3*y^0 = 0

(13/2*y^2-1/3*y^1-5*y^0)/(y^1) = 0 // * y^2

y^1*(13/2*y^2-1/3*y^1-5*y^0) = 0

y^1

(13/2)*y^2+(-1/3)*y-5 = 0

(13/2)*y^2+(-1/3)*y-5 = 0

DELTA = (-1/3)^2-(-5*4*(13/2))

DELTA = 1171/9

DELTA > 0

y = ((1171/9)^(1/2)-(-1/3))/(2*(13/2)) or y = (-(-1/3)-(1171/9)^(1/2))/(2*(13/2))

y = ((1171/9)^(1/2)+1/3)/13 or y = (1/3-(1171/9)^(1/2))/13

y in { (1/3-(1171/9)^(1/2))/13, ((1171/9)^(1/2)+1/3)/13} 

y in { (1/3-(1171/9)^(1/2))/13, ((1171/9)^(1/2)+1/3)/13 }

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