13/2z-7=-37+3/2z

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Solution for 13/2z-7=-37+3/2z equation: 



13/2z-7=-37+3/2z

We move all terms to the left:

13/2z-7-(-37+3/2z)=0



Domain of the equation: 2z!=0

z!=0/2

z!=0

z∈R





Domain of the equation: 2z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

13/2z-(3/2z-37)-7=0

We get rid of parentheses

13/2z-3/2z+37-7=0

We multiply all the terms by the denominator


37*2z-7*2z+13-3=0

We add all the numbers together, and all the variables

37*2z-7*2z+10=0

Wy multiply elements

74z-14z+10=0

We add all the numbers together, and all the variables

60z+10=0

We move all terms containing z to the left, all other terms to the right

60z=-10

z=-10/60

z=-1/6

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