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13/6m-1/2-5/3m=-3/2
We move all terms to the left:
13/6m-1/2-5/3m-(-3/2)=0
Domain of the equation: 6m!=0
m!=0/6
m!=0
m∈R
Domain of the equation: 3m!=0We get rid of parentheses
m!=0/3
m!=0
m∈R
13/6m-5/3m-1/2+3/2=0
We calculate fractions
156m/72m^2+(-120m)/72m^2+(162m^2-1)/72m^2=0
We multiply all the terms by the denominator
156m+(-120m)+(162m^2-1)=0
We get rid of parentheses
162m^2+156m-120m-1=0
We add all the numbers together, and all the variables
162m^2+36m-1=0
a = 162; b = 36; c = -1;
Δ = b2-4ac
Δ = 362-4·162·(-1)
Δ = 1944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1944}=\sqrt{324*6}=\sqrt{324}*\sqrt{6}=18\sqrt{6}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-18\sqrt{6}}{2*162}=\frac{-36-18\sqrt{6}}{324} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+18\sqrt{6}}{2*162}=\frac{-36+18\sqrt{6}}{324} $
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