130+3y=2(4y+9)+2(4y+4)

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Solution for 130+3y=2(4y+9)+2(4y+4) equation:



130+3y=2(4y+9)+2(4y+4)
We move all terms to the left:
130+3y-(2(4y+9)+2(4y+4))=0
We calculate terms in parentheses: -(2(4y+9)+2(4y+4)), so:
2(4y+9)+2(4y+4)
We multiply parentheses
8y+8y+18+8
We add all the numbers together, and all the variables
16y+26
Back to the equation:
-(16y+26)
We get rid of parentheses
3y-16y-26+130=0
We add all the numbers together, and all the variables
-13y+104=0
We move all terms containing y to the left, all other terms to the right
-13y=-104
y=-104/-13
y=+8

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