130=3(2y+-30)-2(y+50)

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Solution for 130=3(2y+-30)-2(y+50) equation: 


Simplifying
130 = 3(2y + -30) + -2(y + 50)

Reorder the terms:
130 = 3(-30 + 2y) + -2(y + 50)
130 = (-30 * 3 + 2y * 3) + -2(y + 50)
130 = (-90 + 6y) + -2(y + 50)

Reorder the terms:
130 = -90 + 6y + -2(50 + y)
130 = -90 + 6y + (50 * -2 + y * -2)
130 = -90 + 6y + (-100 + -2y)

Reorder the terms:
130 = -90 + -100 + 6y + -2y

Combine like terms: -90 + -100 = -190
130 = -190 + 6y + -2y

Combine like terms: 6y + -2y = 4y
130 = -190 + 4y

Solving
130 = -190 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
130 + -4y = -190 + 4y + -4y

Combine like terms: 4y + -4y = 0
130 + -4y = -190 + 0
130 + -4y = -190

Add '-130' to each side of the equation.
130 + -130 + -4y = -190 + -130

Combine like terms: 130 + -130 = 0
0 + -4y = -190 + -130
-4y = -190 + -130

Combine like terms: -190 + -130 = -320
-4y = -320

Divide each side by '-4'.
y = 80

Simplifying
y = 80

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