130=3x+(3/4x)

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Solution for 130=3x+(3/4x) equation: 



130=3x+(3/4x)

We move all terms to the left:

130-(3x+(3/4x))=0



Domain of the equation: 4x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(3x+(+3/4x))+130=0

We multiply all the terms by the denominator


-(3x+(+3+130*4x))=0



We calculate terms in parentheses: -(3x+(+3+130*4x)), so:

3x+(+3+130*4x)

We add all the numbers together, and all the variables

3x+(130*4x+3)

We get rid of parentheses

3x+130*4x+3

Wy multiply elements

3x+520x+3

We add all the numbers together, and all the variables

523x+3

Back to the equation:

-(523x+3)



We get rid of parentheses

-523x-3=0

We move all terms containing x to the left, all other terms to the right

-523x=3

x=3/-523

x=-3/523

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