130=n2+3n

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Solution for 130=n2+3n equation:



130=n2+3n
We move all terms to the left:
130-(n2+3n)=0
We add all the numbers together, and all the variables
-(+n^2+3n)+130=0
We get rid of parentheses
-n^2-3n+130=0
We add all the numbers together, and all the variables
-1n^2-3n+130=0
a = -1; b = -3; c = +130;
Δ = b2-4ac
Δ = -32-4·(-1)·130
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-23}{2*-1}=\frac{-20}{-2} =+10 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+23}{2*-1}=\frac{26}{-2} =-13 $

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