130=n2+3n

Solution for 130=n2+3n equation:

130=n2+3n

We move all terms to the left:

130-(n2+3n)=0

We add all the numbers together, and all the variables

-(+n^2+3n)+130=0

We get rid of parentheses

-n^2-3n+130=0

We add all the numbers together, and all the variables

-1n^2-3n+130=0

a = -1; b = -3; c = +130;
Δ = b2-4ac
Δ = -32-4·(-1)·130
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-23}{2*-1}=\frac{-20}{-2}
=+10
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+23}{2*-1}=\frac{26}{-2}
=-13
$