130=p+2p-10+p/2

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Solution for 130=p+2p-10+p/2 equation:



130=p+2p-10+p/2
We move all terms to the left:
130-(p+2p-10+p/2)=0
We add all the numbers together, and all the variables
-(3p+p/2-10)+130=0
We get rid of parentheses
-3p-p/2+10+130=0
We multiply all the terms by the denominator
-3p*2-p+10*2+130*2=0
We add all the numbers together, and all the variables
-1p-3p*2+280=0
Wy multiply elements
-1p-6p+280=0
We add all the numbers together, and all the variables
-7p+280=0
We move all terms containing p to the left, all other terms to the right
-7p=-280
p=-280/-7
p=+40

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