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130=x/3+(5x-590)
We move all terms to the left:
130-(x/3+(5x-590))=0
Domain of the equation: 3+(5x-590))!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
(5x-590))!=-3
x∈R
-(x+130*3+(5x-590))=0
We calculate terms in parentheses: -(x+130*3+(5x-590)), so:We get rid of parentheses
x+130*3+(5x-590)
determiningTheFunctionDomain x+(5x-590)+130*3
We add all the numbers together, and all the variables
x+(5x-590)+390
We get rid of parentheses
x+5x-590+390
We add all the numbers together, and all the variables
6x-200
Back to the equation:
-(6x-200)
-6x+200=0
We move all terms containing x to the left, all other terms to the right
-6x=-200
x=-200/-6
x=33+1/3
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